Reaction of $R-CONH_2$ with a mixture of $Br_2$ and $KOH$ gives $R-NH_2$ as the main product. The intermediates involved in this reaction are :-
$(A)$ $R-CONHBr$
$(B)$ $R-NH-Br$
$(C)$ $R-N=C=O$
$(D)$ $R-CONBr_2$

  • A
    $A, B$
  • B
    $A, D$
  • C
    $A, C$
  • D
    $A, B, D$

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Consider the following reaction. The product $X$ is used:

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